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3 years ago

What's the answer ?????

Mathematics

2 answers:

inysia [295]3 years ago

8 0

Ummm...... i would say B, i hope that helped! if not, forgive me :)

Nezavi [6.7K]3 years ago

7 0

I hope this helps you

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A square has sides of length s a rectangle is 6 inches shorter and 1 inch longer than the square. Which of the following polynom

harkovskaia [24]

I think the answer is C

5 0

2 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago

Please help 10 FREE POINTS!!!!

Maurinko [17]

Answer:

364.5

Step-by-step explanation:

you would need a calculator for it, unless you can do exponential math at such a degree... if you're using a PC there's a good graphing calculator at Desmos.com, it can show you how a graph looks, which shows that when n is 7, the answer is 364.5. also it wouldn't be 1093.5 because the exponent is n-1 which means that while n could be 7, you need to take away 1 before using it as an exponent.

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2 years ago

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Annies car used 100 cups of gasoline during a drive he paid $3.12 per gallon for gas. how much did the gas cost ?

VladimirAG [237]

The gas would have cost $19.50. Hope this helps :)

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2 years ago

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A chest shaped as a rectangular prism can hold 576 wooden cube blocks with edge lengths of 1/4 ft.

eduard

The answer is 9 you have to multiply 1/4 three times which gives you 1/64 then you take 576 and multiply it by 1/64 which gives you 9. Hope this helps.

4 0

2 years ago

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