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vivado [14]
2 years ago
6

A sample of iron ore has a density of 7.87 what is its mass? Show all of your work. If it measures 7.5 cm x 2.53 em x 7.15 cm,

Mathematics
1 answer:
mr_godi [17]2 years ago
7 0

Answer:

Mass=1068gr

Step-by-step explanation:

Volume= 7.5 cm x 2.53 cm x 7.15 cm=135.7cm^3

Density=7.87gr/cm^3

Mass=Density*Volume=135.7*7.87=1068gr

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Since the basis is from year 1 to year 2, calculate first for the difference of their percentages. That would be:

Difference = year 2 - year 1
Difference = 2.32% - 1.1% = 1.22%

We apply this same value of percentage increase from year 2 to year. Thus, the percentage for year 3 is:

% Year 3 = % Year 2 + percentage increase
% Year 3 = 2.32% + 1.22%
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6 0
2 years ago
A textbook store sold a combined total of 426 math and sociology textbooks in a week. The number of math textbooks sold was 88 m
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Let m and s be the number of math and sociology books sold respectively.

m=s+88 we are also told that:

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s+88+s=426 combine like terms on left side

2s+88=426  subtract 88 from both sides

2s=338  divide both sides by 2

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8 0
3 years ago
Please help me with 6-9!!
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How many feet are in 9 meters? <br> 1 m = 3.3 ft<br><br><br>9 m = [?] ft​
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8 0
3 years ago
Read 2 more answers
Construct a 99​% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s
vivado [14]

Using the z-distribution, the 99​% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 99% confidence level, hence\alpha = 0.99, z is the value of Z that has a p-value of \frac{1+0.99}{2} = 0.995, so the critical value is z = 2.575.

The estimate and the sample size are given by:

\pi = 0.36, n = 100.

Then the bounds of the interval are:

  • \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.2364
  • \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.4836

The 99​% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
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