L1: 2x+4y-3=0 ..........(1)
P: (2,0)
The point on the line L1 closest to the given point P is at the intersection of L1 with L2, which is the perpendicular passing through P.
Slope of L1=-2/4=-1/2
Slope of L2=-1/(-1/2)=2
Since it passes throug P(2,0), we can use the point-slope formula:
(y-0)=2(x-2) =>
L2: 2x-y-4=0.............(2)
Solve for x & y using (1) and (2) to get intersection point required:
(1)-(2)
2x-2x + 4y-(-y) -3 -(-4) =0
5y=-1, y=-1/5
Substitute y=1/5 in equation (1)
2x+4(-1/5)-3=0 =>
2x-19/5=0
x=19/10
=> the point on L1 closest to (2,0) is (19/10, -1/5)
Answer:
81.2 feet (nearest tenth)
Step-by-step explanation:
If you are looking for an expression it would be x < 4 and the < has a line underneath for less than or equal to. If this is right could I possibly have brainliest? Hope this helped!! :)
Answer:
Volume = 10562.96 cu ft
10.56 hr. to drain all the water
Step-by-step explanation:
V = 1/3Bh B = area of the base h = height
The base is a circle, so 
= 10562.96 cu ft
10562.96/1000 = 10.56 hr.
Euclid's fifth postulate states, rather wordily, that:
<em>if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, </em><span><em>the two straight lines, if produced indefinitely, meet on that side </em><em>on</em><em> which are the angles less than the two right angles.
</em></span>
<em />If that sounds like a mouthful to you, you're not alone. Geometers throughout history found that postulate incredibly awkwardly-worded compared with his other four, and many in the 19th century rejected it outright and created a number of interesting new geometries from its ashes.
Euclid's fifth, put another way, states that two lines that aren't parallel will eventually meet, which consequently implies that <em>two parallel lines will never meet</em>. Without intending it, this property defines the space of Euclid's geometry to be
<em>an infinite flat plane</em>.
If we take that parallel postulate and
throw it out<em>, </em>then we've defined a <em>spherical space</em> for our geometry. Now, it doesn't matter where we draw our lines; <em>all of them will meet at some point</em>. If you need any convincing of this, take a look at the attached image. The longitude lines <em>seem </em>parallel at first, but they all eventually meet at the north and south poles.