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Rzqust [24]
3 years ago
13

Marle placed two orders at the same restaurant last month. In one order, she received 5 trays of lasagna and 3 trays of

Mathematics
1 answer:
user100 [1]3 years ago
5 0

Answer:

$25.25-lasagna, $12.25-garlic bread

Step-by-step explanation:

  5L+3G=163

- 4L+4G=150

______________

 4(5L+3G=163)

-5(4L+4G=150)

_____________

20L+12G=652

-20L-20G=-750

_____________

          -8G=-98

         -8G/-8 = -98/-8

               G=$12.25

now plug that into G in any of the 2 equations at the top and you can solve for L(price of lasagna)

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A smart TV is on sale for 10% off. If the original price is $1,200, what is the sale price?
inysia [295]

Answer:

$1,080 please mark brainliest if satisfied

Step-by-step explanation:

1200 times 0.1 equals 120

1200 minus 120 equals 1080

6 0
2 years ago
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Can someone help me with this ?
zhannawk [14.2K]

Answer:

50

Step-by-step explanation:

12x + 15 = 5x +  85   {Subtract 15 from both sides}

12x + 15 - 15 = 5x + 85 - 15  

          12x = 5x + 70        {Subtract 5x from both sides}

12x - 5x   = 70

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3 years ago
How to solve 42=3(2-3h)
faust18 [17]

Answer:

h= -4.

Step-by-step explanation:

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5 0
3 years ago
A nonprofit organization sent mailing labels along with a request for donations to a random sample of 75,000 potential donors on
Law Incorporation [45]

Answer:

Check the explanation

Step-by-step explanation:

The null and alternative hypotheses in symbols and words are as follows:

: p ≤ 0.06 (There has been no change in the contribution rate due to addition of the mailing labels)

: p > 0.06 (The addition of the mailing labels has increased the contribution rate)

Test Statistics

The following information is provided: The sample size is N = 75000, the number of favorable cases is X = 5625, and the sample

The z-statistic is computed as follows:

- P_0 (1 -

Test statistic z = 17.297

P-value

P-value corresponding to z = 17.297 for a two tailed test is obtained using standard normal table.

p-value = 0.0000

90% Confidence Interval Calculation

Kindly check the attached image below.

Conclusion

Since p-value = 0.0000 < α = 0.05, we reject null hypothesis .

At 0.05 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.

Since the 90% confidence interval (0.073, 0.077) does not contain the hypothesized value 0.06, the result is significant and we reject null hypothesis.

In other words, at 0.10 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.

4 0
3 years ago
A random sample of 100 adults aged 18 years or older were asked to list which ice cream flavor was their favorite. Here are the
DedPeter [7]

Answer:

Pie chart

Step-by-step explanation:

Because they add to 100 a pie chart would be optimal

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