For a number to be a multiple of 6, it must be divisible by 6
and a number divisble by 6 means that it is divisble by 2 and 3
since the ones digit is odd it is not divisble by 2 which means 61 is not a multiple of 6
Answer:
Let's define two transformations.
Vertical translation.
If we have a function f(x), a vertical translation of N untis is written as:
g(x) = f(x) + N
If N is positive, then the translation is upwards
If N is negative, then the translation is downwards.
Horizontal translation.
If we have a function f(x), a horizontal translation of N units is written as:
g(x) = f(x - N)
if N is positive, then the translation is to the right
If N is negative, then the translation is to the left.
Now we have a function g(x) that is a transformation of a parent function f(x) (we actually do not know which parent function, so i assume f(x) = x^2) such that we have a shift right 5 units and up 3 units.
Then:
g(x) = f(x - 5) + 3
and again, using f(x) = x^2
g(x) = (x - 5)^2 + 3
Answer:
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Step-by-step explanation:
Answer:
yes.
2L=4680+520
2L=5200
L=5200:2
L=2600
Step-by-step explanation:
