Question

what are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2 x = ±6 x = ±5 no real solution

Answer 1

Answer:

c

Step-by-step explanation:

.......................

Answer 2

Consider the given quadratic equation $50-x^2=0$

$x^2-50=0$

Comparing the given quadratic equation to the general equation $ax^2+bx+c=0$, we get a= 1, b=0 and c= -50

So, the solution to the quadratic equation is given by:

$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x = \frac{-0 \pm \sqrt{0^2-4(1)(-50)}}{2}$

$x = \frac{\pm \sqrt{200}}{2}$

$x = \pm \sqrt2 (5)$

$x = \pm 5\sqrt2$

So, the solutions to the given quadratic equation are $x = \pm 5\sqrt2$.