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3 years ago

Find the slope of the graphed line

Mathematics

1 answer:

Anna [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Pick two points on the line

(0,-5) and (1,-1)

We can find the slope using

m = (y2-y1)/(x2-x1)

= ( -1 - -5)/(1 - 0)

(-1+5)/(1-0)

4/1

= 4

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National Income (NI) is the sum of the incomes that all individuals in an economy earn in the forms of wages,

Dennis_Churaev [7]

Answer:

\simeq 14.94 billion dollars

Step-by-step explanation:

During the period 1994 - 2004, the 'National Income' ,(NI) of Australia grew about 5.2% per year (measured in 2003 U. S, dollars). In 1994 , the NI of Australia was $ 4 billion.

Now,

(2020 - 1994) = 26

Assuming this rate of growth continues, the NI of Australia in the year 2020 (in billion dollars) will be,

$4 \times[\frac{(100 + 5.2)}{100}}]^{26}$

= $4 \times[\frac{105.2}{100}]^{26}$

=\simeq 14.94 billion dollars (answer)

8 0

3 years ago

Pls help !!! pleaseee.

ladessa [460]

I guess B. That statement is grammatically incorrect.

8 0

2 years ago

Item 21

Pavlova-9 [17]

Answer:

1st: 5x

2nd: 6ft

Step-by-step explanation:

I really don't know how just got the answer right.

5 0

3 years ago

What is the area of the following trapezoid

nignag [31]

Answer:

d. 130

Step-by-step explanation:

3 0

2 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$

(because the point $(x,y)=(6,1)$ corresponds to $(u,v)=(1,2)$ )

$\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}$

4 0

3 years ago