(0, 0) <span>P = <span> ⇒ 0</span></span>
(0, 15) <span>P = <span> ⇒ 1200</span></span>
(6, 12) <span>P = <span> ⇒ 1260</span></span>
Answer:
![\sqrt{65}](https://tex.z-dn.net/?f=%5Csqrt%7B65%7D)
Step-by-step explanation:
distance between two points:
![d=\sqrt{(x_{2}-x_{1})^{2}+( y_{2}-y_{1})^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28%20y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D)
we have:
![d=\sqrt{(-4-(-5))^{2}+(-5-3)^{2}} \\\\d=\sqrt{1^{2}+(-8)^{2}} \\\\d=\sqrt{65}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-4-%28-5%29%29%5E%7B2%7D%2B%28-5-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5Cd%3D%5Csqrt%7B1%5E%7B2%7D%2B%28-8%29%5E%7B2%7D%7D%20%5C%5C%5C%5Cd%3D%5Csqrt%7B65%7D)
Answer: Option C)1 over 15 minus 1 over x equals 1 over 20
Explanation:
Since, Micah can fill a box with books in 15 minutes.
Therefore, the work done by Micah in one minute= 1/15
Also, Sydney takes the books out puts them on a shelf.
And the times taken by Micah when Sydney is also taking the books outside from the self= 20 minutes
Therefore, the work done by Micah in one minute when Sydney taking books out of the box= 1/20
Let Sydney alone takes x minutes to take books outsides the shelf.
Then, work done by Sydney in one minute=1/x
Thus, the work done by Sydney( by taking books out of the box)= the work done by Micah - work done by Micah and Sydney simultaneously= 1/15-1/20
⇒1/x=1/15-1/20
⇒1/15-1/20=1/x
⇒1/15-1/x=1/20 is the required expression.
Therefore, Option C is correct.
Answer:
![y+1=-2(x-5)](https://tex.z-dn.net/?f=y%2B1%3D-2%28x-5%29)
Step-by-step explanation:
We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point given and a slope from the equation. We will chose point-slope since we have a point and the slope.
We will substitute
and
.
![y+1=-2(x-5)](https://tex.z-dn.net/?f=y%2B1%3D-2%28x-5%29)
This is the equation of the line with slope -2 that passes through (5,-1).