The area would be 83.67 cm.
A semicircle is half of a circle. The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle. The formula for circumference is:
C=πd
Using our information, we have
22.92 = 0.5(3.14)d
22.92 = 1.57d
Divide both sides by 1.57:
22.92/1.57 = 1.57d/1.57
14.6≈d
Since the diameter is 14.6, the radius is 14.6/2 = 7.3.
We use the radius for the area of the semicircle:
A=0.5πr²
=0.5(3.14)(7.3)²
=83.67
Answer:
27°
Step-by-step explanation:
- A tangent meets a radius at 90°
- Angles in a trainable sum to 180°
- 180 - 90 - 63 = 27°
Ratio and propoertion
cost/amount is constant
1235/95=x/285
cross multiply or time both sides by (95 times 283)
351975=95x
divide oth sies by 95
3705=x
the cost is $3705
Answer:
A. 
Step-by-step explanation:
For this problem, we have to combine like terms.
Let's look at the equation:
, 
, 
do not have any other like terms, so we keep all in the final answer.
and 
are like terms, so we combine them. 
14 and 6 are like terms, so we combine them. 14+6 = 20
Let's put everything into the final equation:
So, the final answer is A.
Hope this helps! If you have any questions about my work, leave them in the comments below!
Answer:
H0: σ1=σ2
Ha : σ1 >σ2
B. Upper H 0H0:
sigma Subscript 1 Superscript 2σ21equals=sigma Subscript 2 Superscript 2σ22
Upper H 1H1:
sigma Subscript 1 Superscript 2σ21greater than>sigma Subscript 2 Superscript 2σ22
Step-by-step explanation:
The claim is that the treatment group has errors that <em><u>vary significantly</u></em> more than the errors of the placebo group.
The claim is the alternative hypothesis and the opposite of claim is the null hypothesis.
Vary significantly means that it is greater than so we choose the alternate hypothesis of greater than and the null hypothesis will be equal to errors of the placebo group.
So the correct choice is B.
B. Upper H 0H0:
sigma Subscript 1 Superscript 2σ21equals=sigma Subscript 2 Superscript 2σ22
Upper H 1H1:
sigma Subscript 1 Superscript 2σ21greater than>sigma Subscript 2 Superscript 2σ22
Choice A,C and D all are incorrect.
This can be written as
H0: σ1=σ2
Ha : σ1 >σ2
