Answer:
the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)
Step-by-step explanation:
We need to factorise the function 
If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50
Checking few numbers:
So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of 
by (x-2) to find other factors
The long division is shown in figure attached.
After long division we get: 
The equation can be further simplified as: (x+5)(x+5) or (x+5)^2
So, the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
Solve one of the equations for y, take that answer and plug into the second equation in place of y. Then solve for x.
Step-by-step explanation:
Need equations if you want actual answer
$400 * 0.13 * 3 = $156
answer is <span>C) $156.00 </span>
