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Neko [114]
3 years ago
15

Which of the following is tge first four terms of the sequence a n=3n+5?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0

c

to generate the first four terms, substitute n = 1, 2, 3, 4 into the formula

a_{1} = (3 × 1) + 5 = 3 + 5 = 8

a_{2} = (3 × 2 ) + 5 = 6 + 5 = 11

a_{3} = (3 × 3) + 5 = 9 + 5 = 14

a_{4} = (3 × 4) + 5 = 12 + 5 = 17

the first four terms are 8, 11, 14, 17 → c


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First, some housekeeping:

cos = 12/13 is incomplete; "cos" must have an argument (input).

cos x = 12/13 is fine; here "cos" has the argument (input) x.

Given that cos x = 12/13, find sin x.  To do this, we'll need to find the length of the opposite side, given that the hypo length is 13 and the adj. side length is 12.

12^2 + opp^2 = 13^2, or            opp^2 = 169-144 = 25.

Then the opp side could be either 5 or -5.  Let's assume that it's +5, and that angle x is in the first quadrant.

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cos 2 is an entirely different kind of problem.  Here you are told what the argument (input) to the cosine function is (it is 2, which here means 2 radians).

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