A group of market women sell at least one of yam, plantain and maize.12 of them sell maize,10 sell yam and 14 sell plantain,5 se
ll plantain and maize,4 sell yam and maize,2 sell yam and plantain only ,while 3 sell all the three items.How many women are in the group?
1 answer:
Let the three items be M, Y and P.
n{M ∩ Y} only = 4-3 = 1
n{M ∩ P) only = 5-3 = 2
n{ Y ∩ P} only = 2
n{M} only = 12-(1+3+2) = 6
n{Y} only = 10-(1+2+3) = 4
n{P} only = 14-(2+3+2) = 7
n{M∩P∩Y} = 3
Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.
You might be interested in
Answer:
A
Step-by-step explanation:
Answer:
The straight one, 4th row.
Step-by-step explanation:
linear graph forms a straight line.
y=mx+c
Answer:
16
Step-by-step explanation:
94/6 = 15.66667
smallest number of boxes = 16
-5x +2/9 +2x- 2/9 =7/9
collect like terms
-3x+0=7/9
cross-multiply
-27x=7
solve for x
x=-7/27