f(x)=40
x=8
so if x=2 it would be 40/8 which is 5
Answer:
5832 ways
Step-by-step explanation:
Since the circle has 8 sectors and there is 4 colour,
Assuming the sectors are numbered 1 to 8,
Sector 1 : can be coloured with any of the 4 colour in 4 ways
Sector 2 can be coloured with any of the remaining 3 colours in 3 ways
Sector 3 in 3 ways without using the colour in sector 2
Sector 4 in 3 ways without using the colour in sector 3
Sector 5 in 3 ways without using the colour in sector 4
Sector 6 in 3 ways without using the colour in sector 5
Sector 7 in 3 ways without using the colour in sector 6
Sector 8 in 2 ways without using the colours in sector 1 and 7
Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways
Step-by-step explanation:
4(3x-2) + 6x(2-1)
10x + 11x
21x
Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
__
We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
