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3 years ago

6

9.6, Part A: Find at least three different rational numbers that are between 9.5 and 9.7 (numbers that are bigger than 9.5 and s

maller than 9.7).

1 answer:

g100num [7]3 years ago

4 0

Tree different rational numbers between 9.5 and 9.7 are; 9.55, 9.6, 9.65.

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PLEASEEE HURRY I WILL GIVE BRAINLEST ITS JUST ONE QUESTION

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I think it’s is A make me brainliest

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3 years ago

The length of a flower garden is 9 meters. The width of the garden, w, is unknown. If the area of the garden is greater

muminat

Answer:

The width should be more than 5 m. So it can be 6,7 ...

Step-by-step explanation:

The length of a flower garden is = 9 m

The width of a flower garden is = w

The area of a flower garden > 45 sq. m

The area of a flower garden = l * b

l * b > 45

9 * b > 45

the width should be more than 5 m. So it can be 6,7 ...

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3 years ago

A line drawn on the coordinate plane passes through the points (5.3) and (9,- 13). What is the equation of the line?

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Answer:

Y=-4x+3

Step-by-step explanation:

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3 years ago

What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$

Substituting,

$E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}$

Factoring out the n and one p from the above expression:

$E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}$

Representing k=x-1 in the above gives us:

$E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}$

This can then be written by the Binomial Formula as:

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4 years ago

Solve -3 = x + x + x.

kozerog [31]

-3 = x + x + x
-3 = 3x
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3 years ago

Read 2 more answers