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Mnenie [13.5K]
3 years ago
15

A movie theater was organizing its movie posters for an upcoming sale they found that for every 5 action movie posters they were

2 animated movie posters
Mathematics
1 answer:
adoni [48]3 years ago
8 0

Answer:

5

Step-by-step explanation:

5

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Enter an inequality that represents the description, and then solve.
Natalija [7]
Tony’s backpack can carry weight up to 22 but not more that that
If the variable n represents the total weight carried by tony
Then ; n less than or equal to (n=1+3+3b
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Where b represents book
4+3b is less or equal to 22
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Therefore Tony’s backpack cannot carry more than 6 books
7 0
1 year ago
Can somone help me with number 23 and 24
tangare [24]

23.

store price = 14 + 0.5(14)

store price = 21

customer price = 21 + 0.08(21)

customer price = 21 + 1.68

customer price = $22.68

24.

formula: A = P(1 + rt)

A = 140(1 + (0.03)(2))

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Hope this helps!! :)

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3 years ago
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Fantom [35]

The answer is B, 4000.                                        

3 0
3 years ago
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

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3 years ago
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