Ask question

Ask question

All categories

katrin2010 [14]

2 years ago

14

A right triangle is shown with an angle that measures 60 degrees. The leg adjacent to the 60 degree angle is labeled 5. The leg

opposite of the 60 degree angle is labeled x. The hypotenuse is labeled 10. Find the value of x. If your answer is not an integer, leave it in simplest radical form. The diagram is not drawn to scale.

1 answer:

Luda [366]2 years ago

6 0

Answer:

$x = 5 \sqrt{3}$

Step-by-step explanation:

Please see the attached pictures for the full solution.

You might be interested in

Triangle DIG is reflected across the l-axis.

drek231 [11]

there is not such thing as an I axis, but I will show you what happens for both x and y axis so you can fill out the assignment with the correct information.

IF you meant flipping over the x axis, then the dot will go from top to bottom, bottom to up, the x position won't change only its height(y position)

This meant that for reflecting across the x axis, (x,y)->(x,-y)

For y axis its the opposite, just flipping to the side.

This meant that for reflecting across the y axis, (x,y)->(-x,y)

7 0

2 years ago

The hypotenuse of a right triangle measures 17 cm and one of its legs measures 8 cm.

riadik2000 [5.3K]

Answer:

15cm

Step-by-step explanation:

c2=a2+b2 thus do the math and 15 comes

3 0

2 years ago

Read 2 more answers

Jasmine is baking and selling cupcakes for $15 per dozen.She would like to make more than $120 in cupcake sales. Which number li

pishuonlain [190]

Answer:

Step-by-step explanation:

Jasmine is baking and selling cupcakes for $15 per dozen.

Let x be the number of dozens of cupcake made by Jasmine.

Her total sales= Sales Per Dozen X Number of Dozens of cupcake sold

= $15 X x = $15x

Since she would like to make more than $120 in cupcake sales.

It means her total sales must be greater than $120.

15x>120

x>120/15

x>8

The number line attached represents the solutions to the situation.

All integers to the right of 8 (excluding 8) satisfies the situation.

3 0

2 years ago

Which function has a constant additive rate of change of -1/4?

VladimirAG [237]

Answer:

The first graph (in other words A)

Step-by-step explanation:

bc it is going down 1/4 at a constant rate!!!

Hope This Helps!!!

<3

7 0

2 years ago

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$

$C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35$

$C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21$

$C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1$

For all the calculations just recall that 4! =24 and 5!=120.

6 0

2 years ago