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Snowcat [4.5K]
3 years ago
8

How do i factor -4c^2+19c+5

Mathematics
1 answer:
Liula [17]3 years ago
3 0

Answer:

-1(4c+1)(c-5)

Step-by-step explanation:

First get rid of the negative by factoring out -1, then determine what factors of 5, the constant term(the number without the x), multiply by 4 to add up to -19. The only factors of 5 are 1 and 5, so we will use these. (4c+1)(c-5) can be "foiled" to check our answer.

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Step-by-step explanation:

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tia_tia [17]
The answer is:
____________________
x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
_______________________
{Otherwise, the question might be "incomplete".}.
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The question seems incomplete; how can we solve for "x" when we do not know what "y" equals?
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However, it could be possible to "solve for x" in terms of "y".  To so this, we need to isolate ""x" on one side of the equation:
_______________________________
Given: <span>y=1/4 (x) + 3 ; Let us multiply the ENTIRE EQUATION (both sides) by "4", to get rid of the "1/4" (fraction coefficent) of "x", and to "cancel out" the "1/4" fraction cofficient of "x" to the implied "1"; to help solve for "x" :
________________________________________
4 *{ </span>y= 1/4 (x) + 3} ;
______________________
4y = x + 12 ; Now we can subtract "12" from EACH SIDE of the equation;                       to isolate "x" on one side of the equation; and to solve for "x":
_______________________
4y - 12 = x + 12 - 12 ;
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4y - 12 = x ; This is our answer:
___________________________
x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
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Step-by-step explanation:

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Step-by-step explanation:

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