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2 years ago

Can someone pls pls help me?

Mathematics

1 answer:

vesna_86 [32]2 years ago

8 0

Answer:

Hello! answer: 9

Step-by-step explanation:

Formula for triangle area: base × height ÷ 2 or base × height × 1/2

6 × 3 = 18 18 ÷ 2 = 9 therefore 9 is the area!

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14a^8c^9 + 2a^4c^3 [Algebra]

rosijanka [135]

Answer:

im not the best at algebra but

2a+3b+4c

Step-by-step explanation:

subtract

(2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

add

=(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

then subtract

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

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2 years ago

I’m stuck on this question

Korolek [52]

F(2y + 1) is 2

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2 years ago

Mr. Thomas deposited 2500 in a new bank account. The bank pays 6.5% interest compounded annually on this account. He makes no de

kotykmax [81]

Answer:

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Step-by-step explanation:

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2 years ago

What is the value of x in the figure shown below?

Gnoma [55]

Answer: Haha I don't know the answer---Wait wait--I know the answer, its Do School and study for it and you'll find out :)

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1 year ago

Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a

krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. <u>Finding z-score for Reagan;</u>

Let X = distribution of SAT scores

SO, X ~ Normal( $\mu=1000, \sigma^{2}=100^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1000

$\sigma$ = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

z-score = $\frac{1140-1000}{100}$ = 1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal( $\mu=17, \sigma^{2}=5^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 17

$\sigma$ = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

z-score = $\frac{30-17}{5}$ = 2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

6 0

2 years ago