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2 years ago

Factorize completely 81k^2 - m^2

Mathematics

2 answers:

Genrish500 [490]2 years ago

7 0

81k^2 - m^2 factors to

(9k + m)(9k - m)

Prove this by FOILing.

First - 81k^2

Outer - (-9km)

Inner - 9km

Last - (-m^2)

Put it into equation form

81k^2 - 9km + 9km - m^2

And combine terms to get the original equation,

81k^2 - m^2.

⭐ Answered by Hyperrspace (Ace) ⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

PolarNik [594]2 years ago

5 0

(9k+m) X (9k - m)

Step-by-step explanation:

81 $k^{2}$ - $m^{2}$

= (9k)^2 - (m)^2 ( taking the square roots)

=(9k+m) (9k - m)

here we have applied the rules of a^2 - b^2 = ( a+b) ( a -b)

here 9k is taking as a and m is taking as b

thus you get your answer.

hope it helps.

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