Here we will use the trial and error method.
- We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>
<h2>Now,</h2><h3>x=2</h3>
<h2>Again,</h2><h3>x=3</h3>
<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
Then answer would be
90° < 0 < 180°.
hope it helps!
At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ
Now, we need to know when the population will be less than 170.
So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n
n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
Answer: =4c^3-7c^2+4c
Step-by-step explanation:
The scale 1:35 indicates that for every 1 meter on the scale model, there are really 35 meters in real life.
So if the scale model is 6.6 meters, you would do 35 * 6.6 to find the length in real life, which is 231 meters.
The answer is 231 meters.
