What is the ph of a.010m solution of a weak acid ha that is 4% ionized?

Formic acid (HCO2H) has a dissociation constant of 1.8 _ 104 M. The acid dissociates 1:1. What is the [H+] if 0.1 mole of formic

Umnica [9.8K]

Use the equation for Ka => 1.8 x 10 ^ (-4) = [H+][HCO2-}, these 2 concentrations are equal so, 
1.8 x 10 ^ (-4) = [H+]^2 

and [H+] = 4.2 × 10^-3 M

7 0

3 years ago

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When 1 carbon atom combines with 2 oxygen atoms, the resulting substance is called a

PIT_PIT [208]

Answer:

Carbon Dioxide

Explanation:

Which is a compound:)

7 0

3 years ago

Determine the empirical formulas for compounds with the following percent compositions:

White raven [17]

Answer: a) $CS_2$

b) $CH_2O$

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles$

Moles of S= $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.32}{1.32}=1$

For S = $\frac{2.63}{1.32}=2$

The ratio of C : S = 1:2

Hence the empirical formula is $CS_2$

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.7}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is $CH_2O$

5 0

3 years ago

A balloon with a volume of 38.2 L at 91 psi is allowed to expand into a larger can with a total volume of 77.4 L. What is the pr

adelina 88 [10]

Answer:

45 psi

Explanation:

1) Data:

a) V₁ = 38.2 liter

b) P₁ = 91 psi

c) V₂ = 77.4 liter

d) P₂ = ?

2) Formula:

According to Boyle's law, at constant temperature, the pressure and volume of a fixed amount of gas are inversely related:

PV = constant ⇒P₁V₁ = P₂V₂

3) Solution:

Solve for the unknown: P₂ = P₁V₁ /v₂

Substitute the values: V₂ = 91 psi × 38.2 liter / 77.4 liter = 44.9 9si ≈ 45 psi.

7 0

3 years ago

What is the name of Ptsa?

makkiz [27]

Answer:

p- Toluenesulfonic acid

formula:

CH 3 C 6 H 4 SO 3 H

3 0

3 years ago