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seraphim [82]
3 years ago
8

The pressure of 8.40 L of nitrogen gas in a flexible container is decreased to one-half its original pressure, and its absolute

temperature is increased to double the original temperature. What is the new volume?
Chemistry
1 answer:
ollegr [7]3 years ago
7 0

Answer:

33.6 L

Explanation:

From the question given above, the following data were obtained from:

Initial volume (V1) = 8.40 L L

Initial pressure (P1) = P

Initial temperature (T1) = T

Final pressure (P2) = one-half the original pressure = ½P

Final temperature (T2) = double the original temperature = 2T

Final volume (V2) =.?

Thus, the new volume of the gas can be obtained as follow:

P1V1/ T1 = P2V2 /T2

P × 8.40 / T = ½P × V2 /2T

P × 8.40 / T = P × V2 / 4T

Cross multiply

T × P × V2 = P × 8.40 × 4T

Divide both side by T × P

V2 = (P × 8.40 × 4T) /T × P

V2 = 8.40 × 4

V2 = 33.6 L

Thus, the new volume of the gas is 33.6 L

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For example, shape, size, mass, density etc are all physical properties.

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4 years ago
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sergejj [24]

Answer:

The products are carbon dioxide and water

Explanation:

Step 1: Data given

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I recently did this assignment!

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Answer:

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