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Lelu [443]
3 years ago
9

what pressure will be needed to reduce the volume of 77.4 l of helium at 98.0 kpa to a volume of 60.0 l? 76 kpa 126 kpa

Chemistry
1 answer:
nekit [7.7K]3 years ago
6 0
The system follow the Boyle's Law:

P_1\cdot V_1 = P_2\cdot V_2\ \to\ P_2 = \frac{P_1\cdot V_1}{V_2} = \frac{98\ kPa\cdot 77.4\ L}{60.0\ L} = \bf 126.4\ kPa
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What has the lowest ionization erergy?
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Why are the three atoms are isotopes of magnesium
LenKa [72]

Answer:

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6 0
2 years ago
What is the ph of a 0.006 m koh solution? 1. 11.78 2. 7.00 3. 2.22 4. 8.88 5. 5.12?
Stels [109]
The concentration of OH⁻ is first converted to pOH bu using followinf formula,

                                           pOH  =  -log [OH⁻]
Putting value,
                                           pOH  =  -log (0.006)

                                           pOH  =  2.221
As we know,
                                   pH + pOH  =  14
Solving for pH,
                                   pH  =  14 - pOH
Putting value of pOH,
                                   pH  =  14 - 2.221

                                   pH  =  11.779
Result:
           Option-1
is the correct answer.
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