we have completed 9/36=1/4 of the fence
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
Answer:
88/7 ft = 12.6 ft (nearest tenth)
Step-by-step explanation:
Circumference of a circle = 2
r
<u>Radius of inner circle</u>
Given:
- circumference of inner circle = 22ft
= 22/7
⇒ 22 = 2 x (22/7) x r
⇒ r = 3.5
So the radius of the inner circle is 3.5 ft
<u>Radius of outer circle</u>
If the distance between the inner circle and the outer circle is 2 ft, then the radius of the outer circle = 3.5 + 2 = 5.5
<u>Circumference of outer circle</u>
Therefore, circumference of outer circle:
= 2 x (22/7) x 5.5
= 242/7 ft
<u>Difference between circumferences</u>
Difference = outer circle circumference - inner circle circumference
= 242/7 - 22
= 88/7 ft
= 12.6 ft (nearest tenth)

Actually Welcome to the Concept of the Arithmetic Operation.
====> 5(3+6) + 5*3/ 5(4-1)
=====> 5(9) + 15 / 5(3)
=====> 45+15 / 15
=====> 60/15
======> 4
answer is 4
Answer:
yup i guess
Step-by-step explanayuption: