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Maurinko [17]
4 years ago
14

Which of these could be the graph of f(x) = In x + 2?

Mathematics
2 answers:
ArbitrLikvidat [17]4 years ago
7 0

Answer:

C

Step-by-step explanation:

ln 1 = 0, so f(1) = 0 + 2 = 2.  So we need to find a graph that passes through (1, 2).  Only graph C fits.

Lera25 [3.4K]4 years ago
6 0

Answer:

a

Step-by-step explanation:

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6. Which of the following inequalities will require the inequality symbol to
Ad libitum [116K]

Answer:

Both -6x +7>-5 and 14x-2<12

Step-by-step explanation:

Your question said "Which of the FOLLOWING inequalities require the inequality symbol to be reversed when solving" I hope this means multiple choice because i got both 14x-2<12 and -6x +7>-5 to be reversed when i finished solving them. For 6x +7>-5 I got X < 2, and for 14x-2<12 I got X > -28, therefore those two are correct.

5 0
3 years ago
Can y’all help me with 7 - 12 showing work. Will be giving Brainliest:)) and for 13 and 14 I need help too :)) Help please :((((
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7= 16 lb >16 Oz 16x16=256
8= 1500 lb < 2T 2000+2000
9= 3T>5999 lb 2000x3
10= 1600 Oz > 10 lb 1600÷16=100
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13= pounds=6000 tons= 1, 1.5
4 0
3 years ago
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Lana71 [14]

Answer:

The student can increase the magnetic field of the magnet by using an electromagne.

4 0
3 years ago
A rectangular vegetable patch has a perimeter of 28 meters and an area of 48 square
aliina [53]

Answer:

Length = 8 meters

Width = 6 meters

Step-by-step explanation:

Given the following information:

Perimeter of a rectangular vegetable patch: 2(L + W) = 28 meters

Area = L × W = 48 m²

We can solve for the dimensions by using both equations.

First, let's use the formula for the perimeter of the rectangular vegetable patch, and isolate one of the given variables:

2(L + W) = 28

Divide both sides by 2:

\frac{2(L + W)}{2} = \frac{28}{2}

L + W = 14

Subtract W from both sides to isolate L:

L + W - W = 14 - W

L = 14 - W

Next, we'll take the formula for the area, and substitute the value for the L from our previous step:

A = 48  =  L × W

48  = W × (14 - W)

Distribute W into the parenthesis:

48 = 14W - W²

Add W² and subtract 14W to both sides:

W² - 14W + 48 = 14W - 14W - W² + W²

W² - 14W + 48 = 0   ⇒ This represents a quadratic equation in standard form. We can use the coefficient and constant values to solve for its roots.

a = 1, b = -14, and c = 48

Substitute these values into the quadratic equation:

x = \frac{-b +/- \sqrt{b^{2}-4ac}}{2a}

x = \frac{14 +/- \sqrt{(-14)^{2}-4(1)(48)}}{2(1)}

x = \frac{14 +/- \sqrt{196-192}}{2}

x = \frac{14 +/- \sqrt{4}}{2}

x = \frac{14 + 2}{2}, x = \frac{14 - 2}{2}

x = 8, x = 6

Now, we can substitute these values into the formulas for the perimeter and area to find the true dimensions of the rectangular vegetable patch.

Perimeter: 2(L + W) = 2(8 + 6) = 28 meters

Area = L × W = 8 × 6  = 48 m²

Therefore, the dimensions of the rectangular vegetable patch are:

Length = 8 meters

Width = 6 meters

Dimensions: 8 × 6 meters.

3 0
3 years ago
How to evaluate k-(k-h) use h = 1 and k = 1
Hoochie [10]

k-(k-h)

Plug in k and h

1 - (1 - 1)

1 - 0

1

5 0
3 years ago
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