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3 years ago

Which of these could be the graph of f(x) = In x + 2?

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

7 0

Answer:

Step-by-step explanation:

ln 1 = 0, so f(1) = 0 + 2 = 2. So we need to find a graph that passes through (1, 2). Only graph C fits.

Lera25 [3.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

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If f (x) = 3x + 1 and g(x) = 2x + 1, what is the value of f (g(2))?

just olya [345]

Step-by-step explanation:

= f( g(2) )

= 3(2x + 1) + 1

= 6x + 3 + 1

= 6x + 4

= 6(2) + 4

= 12 + 4

= 16

f(g(2)) = 16

3 0

3 years ago

Evaluate the following expression when x = 3 and y = 4:

JulijaS [17]

I don't understand. What are the values given? Are they values of an x,y plot?
If you plot them they are a straight line with y =6x - 2.9 but I don't know what you mean by when x=3 and y = 4?

5 0

3 years ago

marta [7]

Answer:

a) $(x-2)(x-6) + (y-5)(y-11) =0\Rightarrow (x-4)^{2}+(y+3)^{2}=68\\C(4,-3) \:r=\sqrt{68}$ b) (a,b) (c, d) As long as (a,b) and (c,d) are the endpoints of of the diameter.

Step-by-step explanation:

1) The reduced formula of the Circumference is given by:

$(x-a)^{2}}+(y-b)^{2}=r^{2}$

2) Let's expand the factored one into one closer to the pattern above:

$x^{2}-8x+12+y^{2}+6y-55=0\Rightarrow x^{2}-8x+y^{2}+6y=43$

3) Completing the square for both trinomials:

$(x-4)^{2}+(y+3)^{2}=43+16+9\Rightarrow (x-4)^{2}+(y+3)^{2}=68$

4) In the Reduced Formula, $(x-a)^{2}}+(y-b)^{2}=r^{2}$ ,

$C(a,b) \Rightarrow C(4,-3) \:the\:radius\:is\:r=\sqrt{68} \Rightarrow r=2\sqrt{17}$

b) Using the previous example to show this:

When we factor this way

$(x-a)(x -c) + (y -b)(y-d) = 0$

We are indeed, naming "a" and "b", the coordinates of (a, b) of the first endpoint and "b" and "d" the second endpoint as well.Id est, D (2, 5) and B (6,-11).

The radius, is $\sqrt{68} \cong 8.25$