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Maurinko [17]
3 years ago
14

Which of these could be the graph of f(x) = In x + 2?

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

C

Step-by-step explanation:

ln 1 = 0, so f(1) = 0 + 2 = 2.  So we need to find a graph that passes through (1, 2).  Only graph C fits.

Lera25 [3.4K]3 years ago
6 0

Answer:

a

Step-by-step explanation:

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What is the slope of the line represented by the equation y=- } - 5x?
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The slope of the line represented by y = -5x is "-5".

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y=mx+b

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Please help me, I will give brainliest
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Answer:

        8w² < 4w(150-w)

Step-by-step explanation:

Square area of  living  : w  · w  =  w²

Money spent : 8 · w²

Square area of  artichokes : (150 - w) · w    

Money earned : 4 · w · (150 - w)

Julia manages to save some money every week. That means that the money earned is bigger than the money spent ( the money spent is less than the money earned)

8 · w² < 4 · w · (150 - w)

7 0
2 years ago
In 2002, the Bookstore sold 1000 paperback books and 1500 hardback books. In 2003, the store sold 15% more paperback books and 5
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Given:
2002 sold 1000 paperback books and 1500 hardback books for a total of 2,500 books.

2003 sold 15% more paperback books and 5% more hardback books.
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1500 x 1.05 = 1,575 hardbacks

1150 + 1575 = 2,725

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7 0
3 years ago
Imagine that you would like to purchase a $275,000 home. Using 20% as
vfiekz [6]

Answer:

The mortgage chosen is option A;

15-year mortgage term with a 3% interest rate because it has the lowest total amount paid over the loan term of $270,470

Step-by-step explanation:

The details of the home purchase are;

The price of the home = $275,000

The mode of purchase of the home = Mortgage

The percentage of the loan amount payed as down payment = 20%

The amount used as down payment for the loan = $55,000

The principal of the mortgage borrowed, P = The price of the house - The down payment

∴ P = $275,000 - 20/100 × $275,000 = $275,000 - $55,000 = $220,000

The principal of the mortgage, P = $220,000

The formula for the total amount paid which is the cost of the loan is given as follows;

Outstanding \ Loan \ Balance = \dfrac{P \cdot \left[\left(1+\dfrac{r}{12} \right)^n -  \left(1+\dfrac{r}{12} \right)^m \right] }{1 - \left(1+\dfrac{r}{12} \right)^n }

The formula for monthly payment on a mortgage, 'M', is given as follows;

M = \dfrac{P \cdot \left(\dfrac{r}{12} \right) \cdot \left(1+\dfrac{r}{12} \right)^n }{\left(1+\dfrac{r}{12} \right)^n - 1}

A. When the mortgage term, t = 15-years,

The interest rate, r = 3%

The number of months over which the loan is payed, n = 12·t

∴ n = 12 months/year × 15 years = 180 months

n = 180 months

The monthly payment, 'M', is given as follows;

M =

The total amount paid over the loan term = Cost of the mortgage

Therefore, we have;

220,000*0.05/12*((1 + 0.05/12)^360/( (1 + 0.05/12)^(360) - 1)

M = \dfrac{220,000 \cdot \left(\dfrac{0.03}{12} \right) \cdot \left(1+\dfrac{0.03}{12} \right)^{180} }{\left(1+\dfrac{0.03}{12} \right)^{180} - 1}  \approx 1,519.28

The minimum monthly payment for the loan, M ≈ $1,519.28

The total amount paid over loan term, A = n × M

∴ A ≈ 180 × $1,519.28 = $273,470

The total amount paid over loan term, A ≈ $270,470

B. When t = 20 year and r = 6%, we have;

n = 12 × 20 = 240

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.06}{12} \right) \cdot \left(1+\dfrac{0.06}{12} \right)^{240} }{\left(1+\dfrac{0.06}{12} \right)^{240} - 1}  \approx 1,576.15

The total amount paid over loan term, A = 240 × $1,576.15 ≈ $378.276

The monthly payment, M = $1,576.15

C. When t = 30 year and r = 5%, we have;

n = 12 × 30 = 360

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.05}{12} \right) \cdot \left(1+\dfrac{0.05}{12} \right)^{360} }{\left(1+\dfrac{0.05}{12} \right)^{360} - 1}  \approx 1,181.01

The total amount paid over loan term, A = 360 × $1,181.01 ≈ $425,163

The monthly payment, M ≈ $1,181.01

The mortgage to be chosen is the mortgage with the least total amount paid over the loan term so as to reduce the liability

Therefore;

The mortgage chosen is option A which is a 15-year mortgage term with a 3% interest rate;

The total amount paid over the loan term = $270,470

8 0
3 years ago
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