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Maurinko [17]
4 years ago
14

Which of these could be the graph of f(x) = In x + 2?

Mathematics
2 answers:
ArbitrLikvidat [17]4 years ago
7 0

Answer:

C

Step-by-step explanation:

ln 1 = 0, so f(1) = 0 + 2 = 2.  So we need to find a graph that passes through (1, 2).  Only graph C fits.

Lera25 [3.4K]4 years ago
6 0

Answer:

a

Step-by-step explanation:

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Plzz help and no wrong answer need to be done asap
Ann [662]

Answer:

1/500

Step-by-step explanation:

7 0
2 years ago
1a. What is the product of 2x - 3 and 5x^2 - 2x + 6? Work and Answer:​
kiruha [24]

Answer:

I dont know.. sorry.......

8 0
2 years ago
Read 2 more answers
What are the solutions to the system of equations graphed below?
Lelu [443]

Answer:

D

Step-by-step explanation:

The solution to a system of equations given graphically is at the points of intersection of the 2 graphs.

These occur at (4, 8 ) and (0, - 8 ) → D

4 0
3 years ago
A = 6 and b = 24 work out the values a) a+b b) ab c) b/a d) d) (a+b)^2
Oksanka [162]

Answer:

a) 30

b) 144

c) 4

d) 900

Step-by-step explanation:

a) 6 + 24 = 30

b) 6 * 24 = 144

c) 24 ÷ 6 = 4

d) 30^2=900

5 0
3 years ago
Read 2 more answers
A stadium has 45,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. If section C held 300 fewer
White raven [17]

Answer:

Let's define the variables:

A = number of seats in section A.

B = number of seats in section B.

C = number of seats in section C.

We have the equations:

A + B + C = 45,000.

C - 300 = B/2

A*$28 + B*$24 + C*$20 = $1,139,200

This is a system of equations, the first step to solve this is to isolate one variable in one of the equations, and then replace it in the others.

I will isolate C in the second equation:

C = B/2 + 300.

Now let's replace this in the other two equations:

A + B + B/2 + 300 = 45,000

A*$28 + B*$24 + (B/2 + 300)*$20 = $1,139,200

Let's simplify these equations:

A + B*(3/2) = 44,700

A*$28 + B*$34 + $6,000 = $1,139,200

Now let's isolate A in the first equation:

A = 44,700 - B*(3/2)

Let's replace this in the other equation:

(44,700 - B*(3/2))*$28 + B*$34 + $6,000 = $1,139,200

Now let's solve this for B.

-B*$8 + $1,252,200 = $1,139,200

-B*$8 =  $1,139,200 - $1,252,200  = -$113,000

B = $113,000/8 = 14,125

Now we can replace that in the equations:

A =  44,700 - B*(3/2) =  44,700 - 14,125*(3/2) = 23,512.5, that we should round up to 23,513.

And C = B/2 + 300 = 7362.5

As we rounded the previous one up, we should round this one down to 7362.

3 0
3 years ago
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