The answer

the complement of the question is

What is the value of y?

2
5
7
<span>8
</span>
According to the image, HKJ and FGH are similar, we can apply the theorem of thales
since GK and GF are parallels, so

HK / HF = HJ / HG = KJ / GF and as we see on the figure, HK = HF /2, this implies 2HK =HF

HK / 2HK = KJ / GF it is equivalent to 1/2 = 2y+5 / 5y +3

likewise, equivalent to 5y +3 = 4y +10, 5y-4y = 10-3, and y = 7

so the answer is 7

7 0

3 years ago

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Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$

4 0

3 years ago