Choose the graph that correctly corresponds to the equation x = −4. (5 points)
2 answers:
Answer:
Option D is true. ( graph of a vertical line through the point (negative 4,0) )
Step-by-step explanation:
We have to choose a graph such that it corresponds to the equation x= -4.
We know that the graph of x= -4 is a straight line which passes through (-4,0) such that the value of 'x' is constant all over the real line and the value of y may vary over the real line and such a line is a vertical line parallel to the y-axis.
The graph of such function is attached to the answer.
Hence, option D is correct.
You might be interested in
Answer:
(3, 1)
Step-by-step explanation:
Given the following constraints:
2x + 4y ≤ 10
x + 9y ≤ 12
x ≥ 0
y ≥ 0
We have to first graph the above constraints and secondly, we find the boundary points for the feasible region. This is done by plotting the graphs of 2x + 4y ≤ 10 and x + 9y ≤ 12.
From the graph, the following points satisfy the constraints:
(0,0) , (3,1) , (0,4/3) , (5,0)
Given that:
P = x + 6y
For (0, 0): P = x + 6y = 0 + 6(0) = 0
For (3, 1): P = x + 6y = 3 + 6(1) = 9
For (0, 4/3) P = x + 6y = 0 + 6(4/3) = 8
For (5, 0) P = x + 6y = 5 + 6(0) = 5
To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
<u>Rectangle (a)</u>
<u>Rectangle (b)</u>
<u>Rectangle (c)</u>
<u>Rectangle (d)</u>
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at: