Find the length of one side.
V = s^3
s = cube root of V
V = 729
s = cube root 729
s = 9
Put this into your calculator as 729^0.333333333
It should bring back 9 or 8.999999 something which means 9.
Net
The net is shown below. You will have to do the labeling. But I can tell you what you should label each face as?
Area of one face = s^2
s = 9
Area of one face = 9*9
Area of one face = 81
So when you draw this, each face should be labeled with 81.
It should have it's units (ft^2) if your marker is picky.
Part C
There are 6 sides.
1 side has an area of 81 ft^2
6 sides have an area of 6*81 = 486 ft^2
<u>Given</u>:
Given that O is the center of the circle.
AB is tangent to the circle.
The measure of ∠AOB is 68° and we know that the tangent meets the circle at 90°
We need to determine the measure of ∠ABO.
<u>Measure of ∠ABO:</u>
The measure of ∠ABO can be determined using the triangle sum property.
Applying the property, we have;
Substituting the values, we get;
Adding the values, we have;
Subtracting both sides by 158, we get;
Thus, the measure of ∠ABO is 22°