total number of student in the data set in the dataset is 90
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.
Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.
A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>
Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
Answer:
y = 2x - 7
Step-by-step explanation:
The question is asking for slope-intercept form, y = mx + a.
Given:
(1, -5) and (9, 11)
Find the slope (m) between the two points:
m = (y2 - y1) / (x2 - x1)
x1 = 1
x2 = 9
y1 = -5
y2 = 11
m = ( 11 - (-5) )/(9 - 1)
= 16/8
m = 2
y = 2x + a
Use one of the two points to find a (I will use (1, -5)):
-5 = 2(1) + a
-5 = 2 + a
-7 = a
a = -7
y = 2x + (-7)
y = 2x - 7
2×4=8 because 2 and 4 would be the addends and their less than 5 and it equal an answer between 4 and 10
