Answer:
The correct option is A
Explanation:
In project management, earliest finish time for activity A refers to the earliest start time for succeeding activities such as B and C to start.
Assume that activities A and B comes before C, the earliest finish time for C can be arrived at by computing the earliest start-finish (critical path) of the activity with the largest EF.
That is, if two activities (A and B) come before activity C, one can estimate how long it's going to take to complete activity C if ones knows how long activity B will take (being the activity with the largest earliest finish time).
Cheers!
ioq8oy because of the haoss
Explanation:
Answer:
-the reasons why they should be ethical
-how to communicate professionally
Explanation:
GOT IT RIGHT ON ODYSSEY
It's an incomplete, therefore wrong, description of "<span>B. Browser using a URL to access a web page"
After the nameserver returns the IP address of the domain, the client machine makes the page request from the IP address. The client's browser parses (reads) the HTML code, makes calls to the server for any other files (href, img and media) and displays the HTML content according to visual specifications in the CSS (Cascading Style Sheet).
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Answer:
struct item
{
float previousCost;
float taxAmount;
float updatedCost;
} itemObject;
void calculation(int cost,int quantity,float tax)
{
struct item *itemPointer=&itemObject;
itemPointer->previousCost=(cost) * (quantity);
itemPointer->taxAmount=itemPointer->previousCost * (tax/100);
itemPointer->updatedCost=itemPointer->previousCost+itemPointer->taxAmount;
}
Explanation:
- Define a structure called item that has 3 properties namely previousCost, taxAmount and updatedCost.
- The calculation function takes in 3 parameters and inside the calculation function, make a pointer object of the item structure.
- Calculate the previous cost by multiplying cost with quantity.
- Calculate the tax amount by multiplying previous cost with (tax / 100).
- Calculate the previous cost by adding previous cost with tax amount.
