What is the IQR (Inter Quartile Range) for the data set?

Could someone please explain how to solve for the area?

mixas84 [53]

9514 1404 393

Answer:

779.4 square units

Step-by-step explanation:

You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.

One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...

A = (1/2)r²sin(α)

Since there are n such triangles, the area of the n-gon is ...

A = (n/2)r²sin(360°/n)

__

For a hexagon (n=6) with radius 10√3, the area is ...

A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units

8 0

3 years ago

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Lucy is going to watch a movie in her collection. She has 5 action movies, 4 comedies, and 3 dramas.

blsea [12.9K]

Answer:

3/4

Step-by-step explanation:

5 action+4 comedy+3 drama= 12 total movies

12 will be the denominator of our fraction.

The question asks: What is the probability that the movie she selects is NOT a drama?

So, we add the number of action and comedy movies.

5+4=9

9 is our numerator.

But wait! We have to simplify the fraction 9/12!

9 divided by 3= 3

12 divided by 3= 4

Reduced answer: 3/4

5 0

3 years ago

How can you tell if the solution is one value,all real numbers,or no solutions

zysi [14]

One value: would be a single valued function, or just one answer.

Real numbers would be: natural numbers, whole numbers, integers, rational numbers (fractions and repeating or terminating decimals), and irrational numbers.

No solution: there is no answer to the question.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E%7B8%7D%2A7x%5E%7B3%7D%20%7D%7B3x%5E%7B6%7D%2A7%20%7D" id="TexFormula1" title="

denis23 [38]

Answer:

$a = \dfrac{x^2}{3} \quad \textsf{and} \quad b = \dfrac{x^3}{7}$

Step-by-step explanation:

Given expression:

$\dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7 }$

There are several ways this problem can be approached, and therefore many different answers. The goal is to reduce the given expression to a simple product of two terms in x, set that to the given form 3a⋅7b then solve for a and b.

$\implies \dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7}$

Cancel the common factors 3 and 7:

$\implies \dfrac{\diagup\!\!\!\!3x^{8} \cdot \diagup\!\!\!\!7x^{3} }{\diagup\!\!\!\!3x^{6} \cdot \diagup\!\!\!\!7}$

$\implies \dfrac{x^8 \cdot x^3}{x^6}$

Separate the fraction:

$\implies \dfrac{x^8}{x^6} \cdot x^3$

$\textsf{Apply the quotient rule of exponents} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies x^{8-6} \cdot x^3$

$\implies x^{2} \cdot x^3$

Now equate the simplified expression to the given form:

$\implies x^{2} \cdot x^3=3a \cdot 7b$

Therefore:

$\begin{aligned}x^{2} &=3a \:\: &\textsf{ and }\:\: \quad x^3 &=7b\\ \Rightarrow a & = \dfrac{x^2}{3} & \Rightarrow b & = \dfrac{x^3}{7}\end{aligned}$

However, we could also separate them as:

$\begin{aligned}x^{3} &=3a \:\: &\textsf{ and }\:\: \quad x^2 &=7b\\ \Rightarrow a & = \dfrac{x^3}{3} & \Rightarrow b & = \dfrac{x^2}{7}\end{aligned}$

Another way of writing them would be to go back a few steps and separate the fraction in x terms differently:

$\implies \dfrac{x^8 \cdot x^3}{x^6}=x^8 \cdot \dfrac{x^3}{x^6}=x^8 \cdot x^{-3}$

Therefore, this would give us:

$\begin{aligned}x^{8} &=3a \:\: &\textsf{ and }\:\: \quad x^{-3} &=7b\\ \Rightarrow a & = \dfrac{x^8}{3} & \Rightarrow b & = \dfrac{1}{7x^3}\end{aligned}$

As the given expression reduces to x⁵, we can separate the x term in any way we like, so long as the coefficient of a is ¹/₃ and the coefficient of b is ¹/₇. Therefore, there are many possible answers.

7 0

2 years ago

Read 2 more answers

Whoever gets this right gets brainliest!

Ainat [17]

The slope of function A is 6 more than function B this is because y = 9x + 4 for a function this form the slope is the x - coefficient or in this case 9 and since we already now that the functions slope is 3 subtract 3 from 9 to get the answer 6.

7 0

3 years ago