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3 years ago

Could someone please explain how to solve for the area?

Mathematics

2 answers:

mixas84 [53]3 years ago

8 0

9514 1404 393

Answer:

779.4 square units

Step-by-step explanation:

You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.

One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...

A = (1/2)r²sin(α)

Since there are n such triangles, the area of the n-gon is ...

A = (n/2)r²sin(360°/n)

For a hexagon (n=6) with radius 10√3, the area is ...

A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units

IRINA_888 [86]3 years ago

6 0

Given

=> An Equilateral Hexagon with s = 10√3

To Find

=>The area of the Figure

Step-by-step explanation:

The area of an Equilateral Hexagon = 3√3s²/2

Inserting the value of S

=> 3√3*(10√3)²/2

=> 3√3*300/2

=>3√3*150

=>450√3

=>779.4428

<h2>=> 779.44 squared units</h2>

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What are the options it gives you?

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3 years ago

Hazel knits 5 centimeters of scarf eachnight. After 5 nights of knitting, how manycentimeters of scarf will Hazel have knit into

natta225 [31]

Answer:

Hazel will have knitted 25 centimeters of the scarf

SOLUTION

Problem Statement

We are told Hazel knits 5 centimeters of scarf every night for 5 nights. We are required to find the length of the scarf Hazel will have knitted after 5 nights.

Solution

We are told Hazel makes 5 centimeters of scarf every night. Thus, for each night up till 5 nights, we just need to add the length of scarf Hazel has made.

Let us count for each night.

Night 1:

Hazel makes 5 centimeters of the scarf.

Night 2:

Hazel makes extra 5 centimeters, which means she has made:

$\begin{gathered} (5+5)\text{centimeters} \\ =10\text{ centimeters} \end{gathered}$

Night 3:

Hazel makes extra 5 centimeters, which means she has made:

$\begin{gathered} (10+5)\text{centimeters} \\ =15\text{ centimeters} \end{gathered}$

NIght 4:

Hazel makes extra 5 centimeters, which means she has made:

$\begin{gathered} (15+5)\text{centimeters} \\ =20\text{ centimeters} \end{gathered}$

NIght 5:

Hazel makes extra 5 centimeters, which means she has made:

$\begin{gathered} (20+5)\text{centimeters} \\ =25\text{ centimeters} \end{gathered}$

Final Answer

Thus, Hazel will have knitted 25 centimeters of the scarf

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1 year ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

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2 years ago

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(x² + 10x + 25) -25 +2 =0
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3 years ago

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blondinia [14]

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