Start off by stating your facts. You have a maximum of $8.75. We know that each quarter is 25 cents so we multiply 25x26 equaling 650. Yet we need a decimal so it would be $6.50. Each nickel is worth 5 cents so then you would minus $8.75 and $6.50 getting us to $2.25. Now divide it by 5 cents and you should get 45 nickels. You can also do this by stating that 10 nickels is 50 cents and go until you get 45
9514 1404 393
Answer:
x = 3
Step-by-step explanation:
The whole is equal to the sum of the parts.
DG = DO +GO
20 = (4x +1) + 7
12 = 4x . . . . . . . . . . subtract 8
3 = x . . . . . . . . . . . divide by 4
Answer:
PEMDAS
[(30+6)-3^2] ÷ by 9·2
[(30+6)-9] ÷ by 9·2
[(36)-9] ÷ by 9·2
(27) ÷ by 9·2
Division comes first in this equation. Multiplication & Division goes from left to right when using PEMDAS. Same thing goes for Addition & Subtraction.
[(27) ÷ 9] · 2
(3) · 2
Answer: 6
Hopefully that made sense!
Step-by-step explanation:
Answer:
1) How does "Abe" relate to the merry-go-round? (The problem doesn't seem to say.)
2) How many people did each person provide for? So how many dozens were brought? How many are in a dozen? So how many cookies were brought?
Step-by-step explanation:
nm the top
There are n seats on a merry- go-round. A boy takes n rides. Between each ride, he moves clockwise a certain number of places to a new horse. Each time he moves a different number of places. Find all n for which the boy ends up riding each horse.
2) So if there are n horses, first the boy could move by one place then he could move by n+1 places then by 2n+1 so on and so forth, until he moves (n−2)n+1 places, in which case he'd would have been ridden each horse only one time and taken unique number of steps, which implies that all n's satisfy given condition.
1) I don't know how to cancer this let me resheerch and ill get back to you
P>S let this be help only if you need to annotate or reword thx
