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Aliun [14]
3 years ago
14

|25 POINTS| Suppose you have one pyramid with a base that is 10 meters long and 10 meters wide with a slant that is 15 meters. N

ow, if the length of the base is increased to 15 meters, what is the difference in the surface area between the new pyramid and the old pyramid?
125 meters squared.
525 meters squared.
600 meters squared.
400 meters squared.
Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

125 meters squared

Step-by-step explanation:

Surface area of initial pyramid:

  • A= 10²+4*1/2*10*15= 400 m²

Surface area of extended pyramid:

  • A= 10*15+2*1/2*15*15+2*1/2*10*15= 525 m²

The difference is:

  • 525- 400= 125 m²
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To find the final term to compete the square you need to divide the 'x' term by 2 then square it

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3 years ago
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Three brothers Charlie Robert and Nicholas have 21 video games Charlie has twice as many games as Robert. Robert has 5 fewer gam
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Answer:

The equation would be 4x-15=21.

Step-by-step explanation:

Given;

Total Number of Video games = 21

Let the number of video game Nicholas has be 'x'.

Now Given:

Robert has 5 fewer games than Nicholas.

so we can say that;

number of video game Robert has = x-5

Also Given:

Charlie has twice as many games as Robert.

so we can say that;

number of video game Charlie has = 2(x-5)=2x-10

we need to write the equation.

Solution:

Now we can say that;

Total Number of Video games is equal to sum of number of video game Nicholas has, number of video game Robert has and number of video game Charlie has.

framing the equation we get;

x+x-5+2x-10=21\\\\4x-15=21

Hence The equation would be 4x-15=21.

On Solving we get;

Adding both side by 15 we get;

4x-15+15=21+15\\\\4x=36

Dividing both side by 4 we get;

\frac{3x}{4}=\frac{36}{4}\\\\x=9

Hence Nicholas has = 9 video games

Robert has = x-5= 9-5=4 video games

Charlie has = 2x-10 = 2\times9-10=18-10=8 video games

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Answer:

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Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

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All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

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