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AVprozaik [17]
3 years ago
13

Mr.mathis owes $269 on a auto loan. write an integer to represent this situation

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0
He has -269 dollars available, symbolizing he is in debt.
You might be interested in
Given the equation 2x − 5 = 8, which order of operations completely solves for x?
blagie [28]

2x - 5 = 8      Add 5 on both sides

2x - 5 + 5 = 8 + 5

2x = 13          Divide 2 on both sides to get "x" by itself

x = \frac{13}{2}


So addition and division

4 0
3 years ago
En un distrito, hay una calle peatonal. El municipio decidió colocar faroles, bancas y sembrar árboles para mejorar el ornamento
olga_2 [115]

Answer:

El lugar donde la linterna, los bancos y los árboles se encuentran nuevamente está a 300 metros del punto de inicio.

Step-by-step explanation:

Los parámetros dados son;

El espacio entre las linternas = 30 metros.

El espacio entre los bancos = 20 metros.

El espacio entre los árboles = 50 metros.

Por lo tanto, tenemos, la ubicación donde la linterna, los bancos y los árboles se encuentran nuevamente, está dada por el mínimo común múltiplo de cada una de sus distancias de separación individuales como sigue;

      2   divide   30   20   50 {}  

{}      <u>5  divide    15    10    25</u>

{}                           3      2    5

El LCM = 2 × 5 × 3 × 2 × 5 = 300

El lugar donde la linterna, los bancos y los árboles se vuelven a encontrar está a 300 metros del punto de inicio.

6 0
2 years ago
Bart makes $1,000 per month plus his commission on sales. He gets 6 percent of everything he sells. If he sells an $850 mattress
mamaluj [8]
$1,051. You first multiply 850 by 0.06, or 6 percent, to get $51. then add to his monthly salary. Hope this helps
8 0
3 years ago
Read 3 more answers
3. What is the last step to complete a perpendicular bisector construction? *
Furkat [3]

Its

C. Draw a line connecting the the intersection of the arcs below and above the segment.

6 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
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