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brilliants [131]
3 years ago
6

Factor completely (3x^2-12x)(x^2-2x+1)

Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

3x (x-4) (x-1)²

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one evening, 2/3 of the students in Rick's class watched television. of this students, 3/8 watched a reality show. Of the studen
Dimas [21]

Answer:

0.0625 of the students recorded the show.

Step-by-step explanation:

2/3×3/8×1/4= the fraction of people who watched and recorded the show (0.0625)

6 0
3 years ago
Easy question i will mark braineliest
Yuki888 [10]

Answer:

<h2>0.67</h2>

Step-by-step explanation:

5(y - 3.8) = 4.7(y - 4)

Distribute 5 through the parentheses

5y - 19 = 4.7(y - 4)

Distribute 4.7 through the parentheses

5y - 19 = 4.7y - 18.8

Move ' 4.7 y ' to L.H.S and change it's sign

5y - 4.7y - 19 =  - 18.8

Move constant to R.H.S and change it's sign

5y - 4.7y =  - 18.8 + 19

Collect like terms

0.3y =  - 18.8 + 19

Calculate

0.3y = 0.2

Divide both sides of the equation by 0.3

\frac{0.3y}{0.3}  =  \frac{0.2}{0.3}

Calculate

y = 0.67

Hope this helps...

Best regards!!

3 0
3 years ago
Read 2 more answers
I’ll make brainlest. help asap pls
Liono4ka [1.6K]

Answer:

(2, -1)

Step-by-step explanation:

We can add the first equation by the second

(4x + 6y = 2)+(-4x + 4y = -12)=

10y=-10

we divide both sides by 10 to get

y=-1

We plug -1 in the second equation to get:

-4x+4(-1)=-12

-4x-4=-12

-4x=-8

Now, we divide both sides by -4

x=2

Hope this helps!

6 0
3 years ago
the sum of the first nine terms of an arithmetic series is 162, and the sum of the first 12 terms is 288. Determine the first fi
Natali5045456 [20]

Answer:

\boxed{\pink{\tt \leadsto Sum \ of \ first \ five \ terms \ is \ 50 . }}

Step-by-step explanation:

Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.

\boxed{\red{\bf \bigg\lgroup For \ answer \ refer \ to \ attachment \bigg\rgroup  }}

<h3><u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>

• The sum of n terms of an AP is

\boxed{\orange{\sf S_n = \dfrac{n}{2}[2a+(n-1)d] }}

• nth term of an AP is given by ,

\boxed{\blue{\sf T_n = a+(n-1)d }}

8 0
3 years ago
Help me please it would help
Alex73 [517]

Answer:

2.) 11(17/21)

3.) -18(3/5)

4.) -28

​​

6 0
3 years ago
Read 2 more answers
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