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frez [133]
3 years ago
9

Describe how to find the sums -4 + 2 and -4 + -2 on a number line

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
7 0
For number 1, you start at zero and go to the left since the four is negative four spaces. Then, you go to the right two spaces since the 2 is positive. Your answer is -2

For number 2, you start at zero and go left four spaces since it is negative and then go two more spaces to the left because it is negative again
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Simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

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Replacing terms with factors

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Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

Using exponent rule: a^m.a^n=a^{m+n}

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=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

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