Test statement #1.
f(x) = -0.3(x - 5)² + 5
This is the equation of a parabola with vertex at (5,5).
Therefore the function is symmetric about x=5.
The statement "The axis of symmetry is x=5" is TRUE.
Test statement #2.
f(x) is defined for all real values of x.
The statement "The domain is {x | x is a real nuber} is TRUE.
Test statement #3.
As x -> -∞, f(x) -> -∞.
f(5) = -0.3*(5-5)^2 + 5 = 5
Therefore f(x) is creasing over (-∞, 5) is TRUE.
Test statement #4.
As x -> +∞, f(x) -> -∞.
Therefore the curve is concave downward., and it has no minimum.
The statement "The minimum is (5,5)" is False.
Test statement #5.
The maximum value of f(x) occurs at the vertex because the curve is concave downward.
The statement "The range is {y | y≥5}" is False.
Answer:
The first three statements are True. The last two statements are False.
This factors out to: <span>(<span><span>3x</span>−4</span>)</span><span>(<span>x+1</span><span>) :)</span></span>
Class 5? I’m not really sure what the question is
C is the answer because no solution doesnt leave off the x axist
Answer:
1.443
Step-by-step explanation:
Hope it helps:)
