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Zolol [24]
4 years ago
14

A student concluded that has infinitely many solutions. Which statement BEST describes the student’s conclusion?

Mathematics
1 answer:
Nastasia [14]4 years ago
5 0

What's the equation?

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Please help me asap!!!
aliya0001 [1]

Answer:

h t t p s : / / w w w . y o u t u b e . c o m / w a t c h ? v = i i k 2 5 w q I u F o

Explanation:

heres a video on the topic (it also gives the answer) (delete the spaces)

4 0
3 years ago
The price of a stock rose from a yearly low of $9.68 to $18.61. what was the stock percent increase from its low price that year
Helga [31]

Answer: i think it is 8.93

Step-by-step explanation:

4 0
3 years ago
Solve for x.
statuscvo [17]

Answer:

The Answer is: x = 1.444 with repeating 4.

Step-by-step explanation:

212x - 34(2x + 5) = 38

212x - 68x - 170 = 38

212x - 68x = 38 + 170

144x = 208

x = 208/144 = 52/35 or 1.444

Proof:

212(1.444) - 34(2(1.444) + 5) = 38

306.128 - 34(7.888) = 38

306.128 -  268.192 = 37.936 or approximately 38

Hope this helps! Have an Awesome Day!!  :-)

7 0
3 years ago
Given: 5n - 42 - 12n: Prove: n = -6<br> Statements : <br><br> Reasons :
OlgaM077 [116]
5*-6-42-12*12*-6=0
the answer is: 0
6 0
3 years ago
In a class of p students, the average (arithmetic mean) of the test scores is 70. in another class of n students, the average of
lys-0071 [83]

First case:

average of test score =70

number of students =p

total score of 'p' students = ( average of test score)*( number of students)

total score of 'p' students =70p

Second case:

average of test score =92

number of students =n

total score of 'n' students = ( average of test score)*( number of students)

total score of 'n' students =92n

total number of students = p+n

total average score =86

so, total score =86(p+n)

total score = total score of 'p' students +total score of 'n' students

86(p+n)=70p+92n

now, we can simplify it

86p+86n=70p+92n

86p-70p=92n-86n

16p=6n

now, we can find p/n

\frac{p}{n}= \frac{6}{16}

\frac{p}{n}= \frac{3}{8}................Answer


5 0
3 years ago
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