Question

Find the coordinates of the three points on the graph of y = (1/2)x² -2x whose x-values are −2, 0, and 4.

Answer 1

Answer:

y = 6

y = 0

y = 0

Step-by-step explanation:

$y=\frac{1}{2}x² -2x$

When, x = -2

$y=\frac{1}{2}\times (-2)^2-2\times(-2)\\\Rightarrow y=\frac{1}{2}4+4\\\Rightarrow y=2+4\\\Rightarrow y=6$

y = 6

When, x = 0

$y=\frac{1}{2}\times (0)^2-2\times(0)\\\Rightarrow y=0+0\\\Rightarrow y=0$

y = 0

When, x = 4

$y=\frac{1}{2}\times (4)^2-2\times(4)\\\Rightarrow y=\frac{1}{2}16-8\\\Rightarrow y=8-8\\\Rightarrow y=0$

y = 0