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nekit [7.7K]
3 years ago
9

What is the rate of change of the woman's shadow when she's 16ft from the street light?

Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0
I’m hungry plz help me please I beg you for food I wasted all my money on a Xbox one X plz help please !
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What’s the correct answer
charle [14.2K]
7-4=3

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8 0
3 years ago
Read 2 more answers
Which pairs of points would result in a line with a rate of change of 2:1? Select all that apply.
Helen [10]

Answer:

Options A, C, D are true.

Step-by-step explanation:

We have to choose the pair of points from that given in the attached file which will result in a line with a rate of change i.e. slope of 2:1 i.e. 2.

A. The points are (-4,-11) and (-2,-7).

Then the slope of the joining line is \frac{-7-(-11)}{-2-(-4)} =2

B. The points are (5,6) and (-5,12).

Then the slope of the joining line is \frac{12-6}{-5-5} =-\frac{3}{5}

C. The points are (0,-3) and (-4,-11).

Then the slope of the joining line is \frac{-11-(-3)}{-4-0} =2

D. The points are (0,-3) and (5,7).

Then the slope of the joining line is \frac{7-(-3)}{5-0} =2

Therefore, options A, C, D are true. (Answer)

7 0
2 years ago
Solve the equation for y.<br> 10x -4y = -20
Vinvika [58]

Answer:

y=5+5/2x

Step-by-step explanation:

7 0
3 years ago
What is 9,846,000,000,000 expressed in scientific notation?
AysviL [449]

Answer:

9.846 × 10¹²

Step-by-step explanation:

You didn't give the powers but that is the answer

5 0
3 years ago
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The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with
NISA [10]

Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

\frac{7}{8} = 0.875

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

= \frac{7}{8 - 7}

= 7

(c) Average time in minutes before service

= λ/[μ(μ - λ)]

= \frac{7}{8(8 - 7)}

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

= \frac{1}{(8 - 7)}

= 1 hour

(e) Probability that a new arrival has to wait for service will be:

λ/μ =

{7}{8}

= 0.875

5 0
3 years ago
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