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timofeeve [1]
2 years ago
7

DMA controllers ____.A) do not utilize an additional, special purpose, processorB) are a nonstandard component in PCs of todayC)

can steal memory access cycles from the main CPUD) can access main memory at the same time as the main CPU
Computers and Technology
1 answer:
otez555 [7]2 years ago
8 0

Answer:

D) can access main memory at the same time as the main CPU

Explanation:

DMA is short for Direct Memory Access, these controllers allow the device to transfer data directly to and from the memory modules without interfering with CPU processes. Therefore it can access main memory at the same time as the main CPU. Thus freeing up CPU processing power for other tasks while also retrieving the data necessary.

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What does ‘‘negotiation’’ mean when discussing network protocols? give an example?
rewona [7]
Some protocols have multiple algorithms to choose from for e.g., cryptographic purposes. During connection set up, client and server negotiate which one they'll use.

One example is the set up of a TLS connection. During the handshake, the client shares a list of its supported ciphers (the 'ciphersuites'). The server responds by indicating the best one that both sides support.

4 0
2 years ago
Meats ages hair and feathers all contain this monomer
OverLord2011 [107]

Answer:Amino Acid

Explanation:

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2 years ago
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Answer:

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6 0
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Read 2 more answers
Consider the following two code segments: Segment 1: while (k > 0) { System.out.println(k); k--; } --------------- Segment 2:
zepelin [54]

Answer:

Always same value

Explanation:

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6 0
3 years ago
The 7-bit ASCII code for the character ‘&’ is: 0100110 An odd parity check bit is now added to this code so 8 bits are trans
Alex787 [66]

Answer

First part:

The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.

Second part:

The invalid bit sequence are option a. 01001000 and d. 11100111

Explanation:

Explanation for first part:

In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.

If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.

If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.  

Explanation for second part:

A valid odd parity bit sequence will always have odd number of 1s.

Since in option a and d,  total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.

And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.

7 0
3 years ago
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