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spayn [35]
3 years ago
10

Write a procedural programming loop.. Your loop should start variable n with a value of 10 and count down to zero. The loop shou

ld terminate when n reaches the value of zero.
Computers and Technology
1 answer:
anastassius [24]3 years ago
3 0

Answer:

//Here is the for loop in C.

for(n=10;n>0;n--)

{

   printf("count =%d \n",n);

}

Explanation:

Since C is a procedural programming language.Here if a loop that starts with n=10; It will run till n becomes 0. When n reaches to 0 then loop terminates otherwise it  print the count of n.

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{  // variables

int n;

// for loop that runs 10 times

// when n==0 then loop terminates

for(n=10;n>0;n--)

{

   cout<<"count ="<<n<<endl;

}

return 0;

}

Output:

count =10

count =9

count =8

count =7

count =6

count =5

count =4

count =3

count =2

count =1

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In Linux, when logged in as a normal user with root privileges, which command must precede the apt-get command in the command li
siniylev [52]

Answer:

"sudo" is the command to get super user or root privileges in linux.

Explanation:

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sudo apt-get install <package name>

8 0
3 years ago
The ---------------initiates a message by encoding theidea (or a thought) in words or symbols and sends it to areceiver.ChannelS
saw5 [17]

Answer:

None of the given options

Explanation:

The sender initiates a message by encoding theidea (or a thought) in words or symbols and sends it to a receiver.

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3 years ago
If you do not want the border style to carry forward each time the enter key is pressed, you need to ____.
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Hope This Helps
-Chris
8 0
3 years ago
Illustrate that the system is in a safe state by demonstrating an order in which the threads may complete.If a request from thre
Kamila [148]

Answer:

a. safe sequence is T2 , T3, T0, T1, T4.

b. As request(T4) = Available, so the request can be granted immediately

c. As request(T2) < Available, so the request can be granted immediately

d. As request(T3) < Available, so the request can be granted immediately.

Explanation:

It will require matrix

[i, j] = Max [i, j] – Allocation [i, j]

A B C D

T0 3 3 3 2

T1 2 1 3 0

T2 0 1 2 0

T3 2 2 2 2

T4 3 4 5 4

Available = (2 2 2 4)

1. Need(T2) < Available so, T2 can take all resources

Available = (2 2 2 4) + (2 4 1 3) (Allocation of T2) = (4 6 3 7)

2. Need(T3)<Available so, T3 will go next

Available = (4 6 3 7) + (4 1 1 0) = (8 7 4 7)

Like wise next T0, T1, T4 will get resources.

So safe sequence is T2 , T3, T0, T1, T4.

(Note, there may be more than one safe sequence).

Solution b.

Request from T4 is (2 2 2 4) and Available is (2 2 2 4)

As request(T4) = Available, so the request can be granted immediately.

Solution c.

Request from T2 is (0 1 1 0) and Available is (2 2 2 4)

As request(T2) < Available, so the request can be granted immediately.

Solution d.

Request from T3 is (2 2 1 2) and Available is (2 2 2 4)

As request(T3) < Available, so the request can be granted immediately.

5 0
3 years ago
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