The density of lead is 11.35 g/cm3 . What is the mass of a piece of lead with a volume of 10.0 cm3 ?
1 answer:
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Answer:
1.89 of Sodium Carbonate
3.94 g of Silver Carbonate
2.43 g of Sodium Nitrate
Zero grams of Silver Nitrate
Explanation:
We have to start with the reaction:
Now, we can balance the reaction:
Now, we have to calculate the limiting reagent and we have to follow a few steps:
1) Convert to moles (using the molar mass of each compound)
2) Divide by the coefficient of each reactive (given by the balanced reaction)
<u>Convert to moles</u>
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<u>Divide by the coefficient</u>
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The smallest value is for
, therefore the 4.86 g of
.
Now we can calculate the amount of compounds produced is we follow a few steps:
1) Use the molar ratio
2) Convert to moles (using the molar mass of each compound)
<u>Amount of Silver Carbonate</u>
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<u>Amount of Sodium Nitrate</u>
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<u>Amount of Sodium Carbonate (Excess reactive)</u>
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<u>Amount of Silver Nitrate</u>
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All the silver nitrate would be consumed in the reaction
I hope it helps!
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