Some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.
<h3>What are hydrocarbons?</h3>
Hydrocarbons are any organic compounds that contain hydrogen and carbon in its structure.
Hydrocarbons can be grouped into the following based on whether they contain single or double bonds:
- Saturated hydrocarbons - contain only single bonds e.g. alkanes
- Unsaturated hydrocarbons - contain double and triple bonds e.g. alkenes
Therefore, it can be said that some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.
Learn more about hydrocarbons at: brainly.com/question/17578846
Answer:
D. Is the correct Option!
----------------------------------------
<u><em>Hope this helps!!! :)</em></u>
Answer:
Carnitine Synthesis
Explanation:
Ascorbic acid acts as a cofactor in various hydroxylation and amidation reactions by electron transfer to enzymes that provide reducing equivalents. Accordingly, ascorbic acid is required or facilitates the conversion of certain proline and lysine residues of the procollagen, the oxidation of lysine side chains to proteins, providing hydroxytrimethylsiline for carnitine synthesis. This means that ascorbic acid is essential for the carnitine synthesis.
Carnitine is derived from amino acids and acts as a cofactor for the enzyme acetyltransferase responsible for the transport of fatty acids to mitochondria. Your presence in the body is very important for feeling energetic and strong. The lack of canitine, influenced by the lack of ascorbic acid in individuals suffering from scurvy, causes a lack of energy.
This is a straightforward dilution calculation that can be done using the equation
where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.
Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:
Substituting in our values, we get
![\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].](https://tex.z-dn.net/?f=%5C%5BM_2%3D%5Cfrac%7B%5Cleft%20%28%2050%20%5Ctext%7B%20mL%7D%20%5Cright%20%29%5Cleft%20%28%200.235%20%5Ctext%7B%20M%7D%20%5Cright%20%29%7D%7B%5Cleft%20%28%20200.0%20%5Ctext%7B%20mL%7D%20%5Cright%20%29%7D%3D%200.05875%20%5Ctext%7B%20M%7D%5C%5D.)
So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.
<u>Science is a systematic enterprise that builds and organizes knowledge in the form of testable explanations and predictions about the universe. The earliest roots of science can be traced to Ancient Egypt and Mesopotamia in around 3000 to 1200 BCE.</u>
