Answer:
Option a (100 kPa) is the appropriate option.
Explanation:
The given value is:
Original pressure,
P₁ = 50 kPa
Let the new pressure be "x".
Now,
⇒ 
On substituting the values, we get
⇒ 
On applying cross-multiplication, we get
⇒ 
⇒ 
Thus the answer above is the right one.
<span>Presumably, any salt-to-water ratio would be low, if the water molecules are not removed from the solution, whatever it may be, as salt is typically a very small potion in saline water.</span>
<span>Displaced volume:
final volume - initial volume :
38.55 mL - 15.75 mL = 22.8 mL
D = m / V
D = 32.138 / 22.8
D = 1.409 g/mL
hope this helps!
</span>
Answer:
Yes
Explanation:
Neither Calcium nor hydrogen nor oxygen are alkali metals
- Alkali metals are Group 1 elements
- They are very soft and mellable.
- H,Li,Na,K,Cs,Fr are included in it however H is not a actual member
Here
Ca(OH)_2 is the compound
Vant Hoff factor is 3
As it's greater than 1 it's a very strong base .
The pOH of this comes around 1.5 to 1.3
So very heavy ionic dissociation
Strong Alkali
Explanation:
when acid reacts with water it form salt and water this reaction is called neutralization reaction