Horse = x = 1 head and 4 feet
Chicken =y = 1 head and 2 feet
Horse + chicken = x + y = 43 ( total heads)
Horse = 43 - y
4x + 2y = 122
4(43-y) + 2y = 122
Simplify:
172-4y + 2y = 122
Combine like terms
172-2y = 122
Subtract 172 from both sides
-2y = -50
Divide both sides by-2
Y = 25
X + y = 43
X + 25 = 43
X = 18
There are 18 horses and 25 chickens.
Answer:
12x+30
Step-by-step explanation:
6(2x+5)
=(6)(2x+5)
=(6)(2x)+(6)(5)
=12x+30
Answer:
B
Step-by-step explanation:
617/500 = 1234/1000
Therefore option B is the answer.
9514 1404 393
Answer:
16
Step-by-step explanation:
48 = 16·3
112 = 16·7
80 = 16·5
3, 5, 7 have no common factors. The GCF of {48, 112, 80} is 16.
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It can be helpful to recognize 48 = 16·3 and 80 = 16·5. A simple check shows 112 = 16·7, so 16 is the GCF.
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You can find GCF(48,112) using Euclid's algorithm:
112 mod 48 = 16
48 mod 16 = 0 ⇒ GCF(48, 112) = 16
and the GCF(16, 80) is ...
80 mod 16 = 0 ⇒ GCF(16, 80) = 16
So, GCF(48, 80, 112) is 16.
The slope of a line perpendicular to the line 6x + 8y = -128 is 4/3.
Given,
The equation of a line = 6x + 8y = -128
We have to convert this into standard form of linear equation, y = mx + b :
So,
6x + 8y = -128
Add -6x to both sides,
6x + 8y - 6x = -6x - 128
Now,
8y = -6x - 128
Divide 8 on both sides
8y/8 = (-6x - 128) / 8
We get,
y = -6/8x - 16
Here, this is in standard form of linear equation.
Here slope of line, m₁ = -6/8
We have to find the slope of line(m₂) which is perpendicular to the given line.
If the line is perpendicular, the slope(m₂) will be the negative reciprocal of the slope(m₁) of the given line.
That is,
Slope of line, (m₂)= -(m₁) = - (-8/6) = 8/6 = 4/3
That is, the slope of the line which is perpendicular to the given line is 4/3.
Learn more about slope of the line here:
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