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Alinara [238K]
4 years ago
9

Three polarizing filters are stacked, with the polarizing axis of the second and third filters at angles of 23.8 ∘ and 65.0 ∘, r

espectively, to that of the first. If unpolarized light is incident on the stack, the light has an intensity of 71.5 W/cm2 after it passes through the stack.
a) If the incident intensity is kept constant, what is theintensity of the light after it has passed through the stack if thesecond polarizer is removed?
Physics
1 answer:
GalinKa [24]4 years ago
4 0

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How can astronomers detect a bianary star if only one of the two stars is visible from earth
Svet_ta [14]

Answer:

The star would continually shift its position from apparently stationary to

reflect the motion of the invisible star around the visible star.

6 0
2 years ago
An astronaut takes a tuning fork with her to the moon she strikes it inside the cabin the cabin is normally filled with air so t
PolarNik [594]

Answer:

The correct option is;

D: Its vibrations are not transmitted to the moon's atmosphere

Explanation:

A tuning fork is used to produce sound by vibration  such that the tune produced is pure

The tune, sound, produced by the tuning fork is transmitted as sound wave through the air by means of the gases of the air as a transmission medium so people at a distance that have air around them can hear the tuning fork sound

On the Moon's surface, the atmosphere is very and it is referred to technically as an exosphere, so the sound of the tuning fork has no medium through which to transmit and therefore, it is not transmitted on the Moon's atmosphere.

6 0
3 years ago
Two rods are identical, except that one is brass (Y = 9.0 × 1010 N/m2) and one is tungsten (Y = 3.6 × 1011 N/m2). A force causes
PIT_PIT [208]

To solve this problem it is necessary to apply the concepts related to Young's Module, and find the radius that gives the ratio between the two given materials. Young's module can be defined as,

Y=\frac{FL}{A \Delta L}

Where,

F= Force

L = Initial Length

A = Cross-sectional Area

\Delta L = Change in Length

Re-arrange the equation to find the change in Length we have,

\Delta L = \frac{FL}{AY}

If both the Force, as the Area and the initial length are considered constant, we can realize directly that the change in length is inversely proportional to Young's Module, therefore

\Delta L \propto \frac{1}{Y}

Applying this concept to that of the two materials (Brass and Tungsten),

\frac{\Delta L_T}{\Delta L_B} = \frac{Y_B}{Y_T}

\frac{\Delta L_T}{\Delta L_B} = \frac{9*10^{10}}{3.6*10^{11}}

\frac{\Delta L_T}{\Delta L_B} = 0.25

If the force caused 3 * 10^ {- 6}m to be stretched, the tungsten will stretch 0.25 of that ratio

L_T = 3*10^{-6}*0.25

L_T = 7.5*10^{-7}m

Therefore the amount of stretch of Tungsten is 7.5*10^{-7}m

8 0
3 years ago
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Friction acts on the ball and causes it to stop 
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