If two lightbulbs are parallel to each other, they have the same brightness. If the same two lightbulbs are put in series with e
1 answer:
You might be interested in
The ray diagram for the given object consists of 2 cm height of object, 4 cm object distance and 3 cm focal length.
<h3>Image formed by a diverging lens</h3>Diverging lens is called a concave lens. The working of the lens is dependent on the refraction of the light rays as they pass through the lens.
Image formed by a diverging lens is always virtual, erect and diminished; smaller than the object and is located on the same side of the lens as the object.
The ray diagram for the given object is presented in the image in the diagram.
- Object height = 2 cm
- Focal length = 3 cm
- Object distance = 4 cm
Learn more about diverging lens here: brainly.com/question/3140453
#SPJ1
Answer:
Force = 21.85N
Explanation:
Given the following data;
Mass = 2.3kg
Acceleration = 9.5m/s²
To find the force;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Substituting into the equation, we have
Force = 2.3 * 9.5
Force = 21.85N
Therefore, the force applied to the rat is 21.85 Newton.
Answer:
C)You should use the thin cooking twine.
Explanation:
A)You can choose either because they are the same length and will produce the same wave speed.
B)You should use the heavy rope.
C)You should use the thin cooking twine.
The speed of wave in a string is given by the following formula:
|| =
Where || = speed of wave,
= tension in the string, and μ = mass per length of the string.
<em>Even though the two strings have the same length, the μ (mass/length) for the heavy rope will be more than the that of a thin rope. Consequently, the </em><em>:μ for the thin rope will be higher than that of the heavy rope and as such, gives a bigger |</em>
<em>|. </em>
Therefore, the thin rope should be used in order to get a faster wave speed in the telephone.
The correct option is C.