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3 years ago

What is the location of the point on the number line that is 4/7 of the way from a = 4 to b = 18?

Mathematics

1 answer:

Sever21 [200]3 years ago

7 0

Answer:

B) 12

Step-by-step explanation:

The difference between a and b = 18 - 4 = 14 units

4/7 of this difference = (4/7) x 14 = 8

the location of the point is hence the value at "a" plus 4/7 of the difference

= 4 + 8

= 12

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Use the graph to find the following.

Levart [38]

a) Local maximum values of g are: 0 and 3

b) The values at which g has local maximum are : -2 and 2

<h3>What is a maximum point?</h3>

A maximum point is the point at which the gradient of the curve changes from positive to negative.

Analysis:

The inverted v-curves all have maximum values and they are two.

The one at x = -2 and the one at x = 2 for in both cases their maximum values are y = 0 and y = 3 respectively.

Learn more about minimum and maximum points: brainly.com/question/14993153

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2 years ago

Carson buys 4 pounds of peaches for $12. How much did he spend per pound?

Inessa [10]

Answer: $3 per pound

Step-by-step explanation:

Since Carson buys 4 pounds of peaches for $12, you can find the value of one pound by dividing 4 by 4. You must also divide the 12 by 4. In conclusion, you pay $3 per pound.

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3 years ago

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Marina CMI [18]

Check the picture below, that's the "inscribed angle theorem"

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3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$